X => -8 -6 -8 3
y => 33 31 39 33
is not a function because the x value -8 results to two different y-values 33 and 39.
Answer:
there is no such number
Step-by-step explanation:
Step-by-step explanation:
It is given that, Katie walks 2 ft forward and 5 ft backwards. We need to find her displacement traveled.
The difference between final position and the initial position is equal to displacement. It is the shorted path covered.
Let forward is +x and backward is -x
Initial position of Katie = +2 ft
Final position of Katie = -5 ft
Displacement = final position - initial position
= -5 - 2
Displacement = -7 ft
So, her displacement is 7 feet in backward direction.
Answer:
i cannot tell where the seperate numbers are and where the x is multiplication and what numbers are negative. post it agian but put spaces in beetween.
Step-by-step explanation:
remember:
PEMDAS
P- parenthases
E- exponents
M- multiplication
D- division
A- addition
S- subtraction
note:
M, D are tied so do it left to right
A, S are tied so do them left to right
For it to be a linear equation, the same difference in x must produce the same difference in y always.
Choice A.
difference in x: 2 - 1 = 1
difference in y: -6 - (-2) = -4
difference in x: 3 - 2 = 1
difference in y: -2 - (-6) = 4
A difference of 1 in x gave a difference of -4 in y and another difference of 1 in x gave a difference of 4 in y.
This is not linear.
Choice B.
difference in x: 2 - 1 = 1
difference in y: -5 - (-2) = -3
difference in x: 3 - 2 = 1
difference in y: -9 - (-5) = -4
A difference of 1 in x gave a difference of -3 in y and another difference of 1 in x gave a difference of -4 in y.
This is not linear.
Choice C.
difference in x: 2 - 1 = 1
difference in y: -10 - (-2) = -8
difference in x: 3 - 2 = 1
difference in y: -18 - (-10) = -8
Do the other differences. All differences in y are -8 corresponding to a difference in x of -1.
This is linear.
Choice D.
The differences in y vary. It is not linear.
Answer: Choice C is linear.
