Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer:
a) 
b) 
Step-by-step explanation:
a) 
1. Distribute the second power (2) outside the first pair of parenthesis:
= 
2. Distribute the third power (3) outside the second pair of parenthesis:
= 
3. Combine like terms:
--------------------------------------------
b) 
1. Factor the number 6 (= 2 · 3):
2. Cancel the common factor (2):
3. Cancel out 
in the numerator an denominator:
hope this helps!
Answer:
The equation of the line is y = 1/4x - 4
Step-by-step explanation:
In order to find this, start with two points that are on the line. We'll use (0, -4) and (4, -3). Now we can use the slope formula to find the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (-4 - -3)/(0 - 4)
m = -1/-4
m = 1/4
Now that we have this, we can use that slope and a point in point-slope form. Then we solve for y to get the equation.
y - y1 = m(x - x1)
y - -4 = 1/4(x - 0)
y + 4 = 1/4x
y = 1/4x - 4
