Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean :
Sample standard deviation :
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer:
Step-by-step explanation:
<u>The line with points (1,2) and (-1,-8). Work out its equation.</u>
<u>The slope is:</u>
- m = (-8 - 2)/(-1 - 1) = -10/-2 = 5
<u>To find the y intercept, substitute x and y-xoordinates of point (1,2):</u>
- 2 = 5(1) + b
- b = 2 - 5
- b = -3
<u>The line is:</u>
<u>Point (x, 17), substitute y-coordinate and solve for x</u>
- 17 = 5x - 3
- 5x = 17 + 3
- 5x = 20
- x = 20/5
- x = 4
Answer:
x= -1/3 or -0.3
Step-by-step explanation:
Mr.willer needs 216 cans because 27 vans times 8 banks equals 216 and 23 times 9 equals 207 so he would need 9 more cans
Answer:
Step-by-step explanation:
<u>Simple Linear Regression
</u>
It a function that represents the relationship between two or more variables in a given data set. It uses the method of the least-squares regression line which minimizes the error between the estimate function and the real data.
Let's compute the best-fit line for the data
First, we find the sums
Then, we compute the averages values
We will also compute the sums of the cross-products and the sum of the squares
We will compute Sxy and Sxx
The slope of the linear regression function is given by
The y-intercept ot the linear function is
Thus the best-fit line is
The correct option is the last one