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dem82 [27]
1 year ago
9

Carlos is draining an aquarium. The graph shows the amount of water ( in liters) in the aquarium versus time ( in minutes

Mathematics
1 answer:
olya-2409 [2.1K]1 year ago
6 0

Using a linear function, we have that:

a) The amount of water in the aquarium at 0 minutes is of 300 liters.

b) As time increases, the amount of water decreases at a rate of 60 liters per minute.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = ax + b

In which:

  • a is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, we have that the y-intercept is of 300, hence the amount of water in the aquarium at 0 minutes is of 300 liters.

The amount <u>decreases 60 liters in a minute,</u> hence:

As time increases, the amount of water decreases at a rate of 60 liters per minute.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

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Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
3 years ago
Write an equation in point-slope form of the line that passes through the point 4,-1and has slope of -5
Basile [38]

Answer:

y=-5+19

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -5. So you can right away fill in the equation for a line somewhat to read:

y=-5x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(4,-1). When x of the line is 4, y of the line must be -1.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,-1).

So, why not plug in for x the number 4 and for y the number -1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(4,-1). y=mx+b or -1=-5 × 4+b, or solving for b: b=-1-(-5)(4). b=19.

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Pachacha [2.7K]
To get a decimal form of a fraction, divide the numerator by the denominator.
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Nadusha1986 [10]
Answer:5
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mr_godi [17]

Answer:

4

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