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EleoNora [17]
1 year ago
10

What is the vertex angle of an isosceles triangle?.

Mathematics
1 answer:
LiRa [457]1 year ago
5 0

The vertex angle is defined as the angle opposite the base. It can be calculated by formula, 180° - 2B = A where, B=base angle and A=vertex angle.

The two sides of an isosceles triangle are congruent, which means they are the same length. The third side of an isosceles triangle is larger than the other two and is known as the base.

Every triangle has three angles that add up to a total of 180°. The base angles are the two angles located along the base of isosceles triangles. In isosceles triangles, the base angles are always congruent, or equal.

The vertex angle is defined as the angle opposite the base. The vertex angle is always greater than the sum of the two base angles. The vertex angle is always calculated by subtracting the base angles from 180°, using the general formula: 180° - 2B = A, where B represents the base angle and A represents the vertex angle.

Thus, vertex angle is defined as the angle opposite the base.

To learn more about isosceles triangle refer here

brainly.com/question/18933031

#SPJ4

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HELP PLEASE<br><br>Question is in the photo.<br><br>I need both Part A and Part B.
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The range of f is the set of all real numbers and the range of f would not change if the value of n is changed

<h3>The range of f when n = 5</h3>

The function is given as:

f(x) =\left \{ {{x - 1;\ \ x < n} \atop {- x + 4;\ \ x \ge n}} \right.

When n = 5, we have:

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<h3>Does changing the value of n change the range?</h3>

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This means that irrespective of the value of n; the range would remain the same

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