What is the vertex angle of an isosceles triangle?.
1 answer:
The vertex angle is defined as the angle opposite the base. It can be calculated by formula, 180° - 2B = A where, B=base angle and A=vertex angle.
The two sides of an isosceles triangle are congruent, which means they are the same length. The third side of an isosceles triangle is larger than the other two and is known as the base.
Every triangle has three angles that add up to a total of 180°. The base angles are the two angles located along the base of isosceles triangles. In isosceles triangles, the base angles are always congruent, or equal.
The vertex angle is defined as the angle opposite the base. The vertex angle is always greater than the sum of the two base angles. The vertex angle is always calculated by subtracting the base angles from 180°, using the general formula: 180° - 2B = A, where B represents the base angle and A represents the vertex angle.
Thus, vertex angle is defined as the angle opposite the base.
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Answer:
The answer is (b)
Step-by-step explanation:
* Lets check how to find the inverse of the matrix,
its dimensions is 2 × 2
* To know if the inverse of the matrix exist find the determinant
- If its not equal 0, then it exist
* How to find the determinant
- It is the difference between the multiplication of
the diagonals of the matrix
Ex: If the matrix is
its determinant = ad - bc
- After that lets swap the positions of a and d, put negatives
in front of b and c, and divide everything by the determinant
- The inverse will be
* Lets do that with our problem
∵ The determinant = (9 × 9) - (-2 × -10) = 81 - 20 = 61
- The determinant ≠ 0, then the inverse is exist
∴ The inverse is =
* The answer is (b)