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Olegator [25]
1 year ago
8

Factor each expression completely6x^2+x-2

Mathematics
1 answer:
Citrus2011 [14]1 year ago
8 0
6x^2+x-2

first , set the function equal to zero

6x^2+x-2=0

now we can use this expression to factor

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

where a is 6, b is 1 and c -2

so, replacing

\begin{gathered} \frac{-(1)\pm\sqrt[]{1^2-4(6)(-2)}}{2(6)} \\  \\ \frac{-1\pm\sqrt[]{1+48}}{12} \\  \\ \frac{-1\pm\sqrt[]{49}}{12} \\  \\ x=\frac{-1\pm7}{12} \end{gathered}

x has two values

x_1=\frac{-1+7}{12}=\frac{1}{2}x_2=\frac{-1-7}{12}=-\frac{2}{3}

we have the two roots now we chang the sign and make the factor expression

(x-\frac{1}{2})(x+\frac{2}{3})

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