Answer:
2(2−1)
Step-by-step explanation:
4−2
Grouping
Common factor
4−2
2(2−1)
Solution
2(2−1)
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer: -5/12
Step-by-step explanation: Before multiplying two fractions together by multiplying across their numerators and multiplying across their denominators, you should always try to cross-cancel as your first step.
So in this problem, the 2 and 8 cross-cancel to 1 and 4.
Also, watch out for your signs. In this problem we have a negative times a positive so we know that our answer will be negative.
Now we can multiply across the numerators and across the denominators.
So we have 5 · 1 which is 5 and 4 · 3 which is 12.
So our answer is -5/12.
Be very careful with your signs!
Subtract a number from the next number.
39 - 45 = -6
Answer: B. -6