Answer:
4/5
Step-by-step explanation:
Answer:
xto the power of three
Step-by-step explanation:
Answer:
recently. The dollar amount collected was $835. Adult tickets, A sold for $8 each and childrens tickets, C sold - 119… ... Adult tickets, A sold for $8 each and childrens tickets, C sold for $5 each. Write a system of ... Now, we need to know how many tickets were sold from both adults and children. Our new ...
1 answer
Step-by-step explanation:
<span>0.5x - 0.1 = -2.9
When you multiply each side of an equation by the same number,
you don't change the equation or its solution. If you want to get rid
of the decimals, you could multiply each side by 10. Then the
equation is
5x - 1 = -29
You should be able to solve that without help.
But I'm about to take your points, so here's
how to solve that equation:
</span><span><span>5x - 1 = -29
Add 1 to each side: 5x = -28
Divide each side by 5 : x = -28 / 5
Simplify the solution: x = -5 and 4/5 .
Again ... this is the same solution as the original equation
if we hadn't gotten rid of the decimals.
</span></span>
Answer:
p ∈ IR - {6}
Step-by-step explanation:
The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2
is all R2 ⇔
And also u and v must be linearly independent.
In order to achieve the final condition, we can make a matrix that belongs to 
using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.
Let's make the matrix :
![A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%26p%262%5Cend%7Barray%7D%5Cright%5D)
We used the first vector ''u'' as the first column of the matrix A
We used the second vector ''v'' as the second column of the matrix A
The determinant of the matrix ''A'' is
We need this determinant to be different to zero
The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that
We can write : p ∈ IR - {6}
Notice that is 
⇒
If we write 
, the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.
