The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
12 times 2 is 24, and 24 times 2 is 48, so there was 48 cookies
Answer:
http://mansfieldalgebra1.weebly.com/uploads/1/0/4/4/10447339/rc_2_answer_key.pdf
Step-by-step explanation:
