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Vika [28.1K]
1 year ago
8

Use the information to find the value cot 0 =

Mathematics
1 answer:
hjlf1 year ago
8 0

The tangent function is given by:

\tan (\theta)=\frac{opposite}{_{\text{ }}adjacent}=\frac{5}{12}

Since the angle is in the 3rd quadrant the opposite side and the adjacent side are negative. So, the cotangent function is given by:

\cot (\theta)=\frac{1}{\tan (\theta)}=\frac{adjacent}{_{\text{ }}opposite}=\frac{-12}{-5}=\frac{12}{5}

Answer:

12/5

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Can you solve number 7, number 8, and number 9
solmaris [256]

Hello!

To solve each expression, you need to substitute the given value for each given variable. If there is an <em>x</em> in the expression, then you substitute 5.07. If there's a <em>y</em>, then you substitute 1.5, and if there's a <em>z</em>, then you substitute 0.403.

7. 3.2x + y (substitute x = 5.07 and y = 1.5)

3.2(5.07) + (1.5)

16.224 + 1.5

17.724

8. yz + x (substitute y = 1.5, z = 0.403, and x = 5.07)

(1.5)(0.403) + (5.07)

0.6045 + 5.07

5.6745

9. z × 7.06 - y (substitute z = 0.403 and y = 1.5)

(0.403) × 7.06 - (1.5)

2.84519 - 1.5

1.34518

<u>Final answers</u>:

  • Number 7: 17.724
  • Number 8: 5.6745
  • Number 9: 1.34518
5 0
3 years ago
What value of "p" will the pair of equations
Nikolay [14]

Answer:

9

Step-by-step explanation:

Slope is the same as coefficient of x

From the equation

3x+4y=12

Y=(-3/4)x+3

The slope for this eqn is -3/4

For this equation

Px+12y=30

12y=-p+30

Y= (-p/12)x +30/12

The slope is -p/12

To get p

-p/12=-3/4

P=9

3 0
3 years ago
Answer pls thanks kfdsdatttdfyui8u90g
diamong [38]

Answer:

Step-by-step explanation:

960 75%

6 0
2 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
Order these numbers from least to greatest. <br><br>5 10/11 <br>117/20 <br>5.84 <br>5.822​
Sliva [168]
Least to greatest: 5 10/11 , 5.822 , 5.84, 117/20.
8 0
3 years ago
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