42=2*3*7
35=5*7
their GCF is 7, so the cats and dogs must be split into 7 groups
42/7=6, and 35/7=5, so there are 6 dogs and 5 cats in each group.
Let (15+x) and (22+x) be the future ages of the brothers
15+x+22+x= 408
Collect like terms
37+2x=408
Move 37 to the other side as a negative number
2x=371
Divide both sides by 2
371/2 is 185.5
So, after 185.5 years, their ages will add up to be 408
Answer:
-1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
Step-by-step explanation:
<u>Step 1: Define</u>
2(3x - 1) ≥ 4x - 6
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 2: 6x - 2 ≥ 4x - 6
- Subtract 4x on both sides: 2x - 2 ≥ -6
- Add 2 on both sides: 2x ≥ -4
- Divide 2 on both sides: x ≥ -2
Here we see that any value <em>x</em> greater than or equal to -2 would work as a solution.
Answer:
maybe u should ask alexa
Step-by-step explanation:
shes my bsf
You have to use the method of FOIL (first, outer, inner and Last)
9b*9b is first
9b*1 is outer
-1*9b is inner
-1*1 is last
Together, they form the expression 81b^2 + 9b - 9b - 1
Collect like terms and the answer is 81b^2 - 1