There is no slope
The x axis’s are the same
Answer:
Q1: p = - 33
Q2: d = - 99
Q3: t = - 13
Step-by-step explanation:
Q1: ![$ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{8} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{3}](https://tex.z-dn.net/?f=%24%20%5Ctextbf%7B-%7D%20%5Cfrac%7B%5Ctextbf%7Bp%7D%7D%7B%5Ctextbf%7B3%7D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B8%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B%3D%7D%20%5Chspace%7B1mm%7D%20%5Ctextbf%7B3%7D)
We solve this taking LCM.
We get: ![$ \frac{-p - 24}{3} = 3 $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B-p%20-%2024%7D%7B3%7D%20%3D%203%20%24)
![$ \implies - p - 24 = 9 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20-%20p%20-%2024%20%3D%209%20%24)
![$ \implies \textbf{p} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 33} $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20%5Ctextbf%7Bp%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B%3D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%2033%7D%20%24)
Q4: ![$ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{4} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B%5Ctextbf%7Bd%7D%7D%7B%5Ctextbf%7B11%7D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B4%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B%3D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%2013%7D%20%24)
Again we proceed like Q1 by taking LCM.
We get: ![$ \frac{d - 44}{11} = - 13 $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7Bd%20-%2044%7D%7B11%7D%20%3D%20-%2013%20%24)
![$ \implies d - 44 = - 13 \times 11 = - 143 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20d%20-%2044%20%3D%20-%2013%20%5Ctimes%2011%20%3D%20-%20143%20%24)
![$ \implies d = - 143 + 44 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20d%20%3D%20-%20143%20%2B%2044%20%24)
![$ \implies \textbf{d} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 99} $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20%5Ctextbf%7Bd%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B%3D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%2099%7D%20%24)
Q7: 5t + 12 = 4t - 1
We club the like terms on either side.
![$ \implies 5t - 4t = - 1 - 12 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%205t%20-%204t%20%3D%20-%201%20-%2012%20%24)
![$ \implies (5 -4)t = - 13 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20%285%20-4%29t%20%3D%20-%2013%20%24)
![$ \implies \textbf{t} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13} $](https://tex.z-dn.net/?f=%24%20%5Cimplies%20%5Ctextbf%7Bt%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B%3D%7D%20%5Chspace%7B1mm%7D%20%20%5Ctextbf%7B-%2013%7D%20%24)
Hence, the answer.
2) (-1,1), (2,-2), (4,-3)
Answer:
The segment area ![= 113.09\ unit^2](https://tex.z-dn.net/?f=%3D%20113.09%5C%20unit%5E2)
Step-by-step explanation:
Area of the segment =
,where
is the angle.
We can also say that
is covered with one segment and we have total
segments (quadrants),so area of the circle divided by
will give us the segement area of the arc.
So area ![\frac{\pi r^2 }{4} =\frac{\pi(12)^2}{4} = 113.09\ units^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20r%5E2%20%7D%7B4%7D%20%3D%5Cfrac%7B%5Cpi%2812%29%5E2%7D%7B4%7D%20%3D%20113.09%5C%20units%5E2)
So the area of the segment ![= 113.09 \ units^2](https://tex.z-dn.net/?f=%3D%20113.09%20%5C%20units%5E2)
Answer:
3(x+2)= 3*x + 3*2
3x * 6 = 18
Step-by-step explanation:
its easy