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zloy xaker [14]

1 year ago

12

Help meeeeeeeeeeeeee pleaseeeeeeeeeeeeeeeeeeeeeeeeee

1 answer:

Sati [7]1 year ago

8 0

Answer:

3K

Step-by-step explanation:

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Cards for Candy Two ladies played cards for candy; the winner received one piece per game from the loser. When it was time for o

Nikitich [7]

Answer:

6 games

Step-by-step explanation:

if one lady had 3 pieces of candy, that means she must have gotten them from the other lady. And since the other lady had only won 3 games, that means that she must have lost an additional 3, so she had to give her candy to the other lady.

8 0

3 years ago

prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.

Vsevolod [243]

Answer:

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ . If we know that $A(x,y) =(-1, 1)$ , $B(x,y) =(-3,4)$ , $C(x,y) = (1,5)$ and $D(x,y) = (3,2)$ , then the measure of each vector is, respectively:

$\overrightarrow{AB} = (-3,4)-(-1,1)$

$\overrightarrow{AB} = (-2, 3)$

$\overrightarrow{DC} = (1,5)-(3,2)$

$\overrightarrow{DC} = ( -2,3)$

$\overrightarrow{AD} = (3,2)-(-1,1)$

$\overrightarrow{AD} = (4, 1)$

$\overrightarrow{BC} = (1,5)-(-3,4)$

$\overrightarrow{BC} = (4, 1)$

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

7 0

3 years ago

Please help! Will give all my points! Due in 30 mins!

Blababa [14]

Answer:

WELP 30 mins passed

Step-by-step explanation:

7 0

3 years ago

. Mr. Donut wants to paint a donut on the wall of his restaurant. The diameter of the outside edge of the donut will be 22 inche

KATRIN_1 [288]

Answer:

The area needed to be painted is approximately 301.44 square inches.

Step-by-step explanation:

The shape of a donut is represented by two concentrical circles, whose area is described by the following formula:

$A =A_{g}-A_{s}$ (Eq. 1)

Where:

$A$ - Total area of the donut, measured in squared inches.

$A_{g}$ - Area of the greater circle, measured in square inches.

$A_{l}$ - Area of the lesser circle, measured in square inches.

By using the definition of the area of the circle, we expand the equation above:

$A = \frac{\pi}{4}\cdot D^{2}_{ext} - A_{s}$ (Eq. 1b)

If we know that $\pi = 3.14$ , $D_{ext} = 22\,in$ and $A_{s} = 78.5\,in^{2}$ , the area needed to be painted is:

$A = \frac{(3.14)\cdot (22\,in)^{2}}{4}-78.5\,in^{2}$

$A \approx 301.44\,in^{2}$

The area needed to be painted is approximately 301.44 square inches.

6 0

3 years ago

Plz help me Answer these Questions plz

Studentka2010 [4]

I need more imformation

7 0

3 years ago