Answer:
The distance between the starting point and the end point
Step-by-step explanation:
The ostrich can run 20 miles in 40 minutes.
<u>Solution:</u>
Given that, An ostrich run 6 mile in 12 minutes
We have to find how far he could come in 40 minutes
Now, according to the given information
Ostrich runs 6 miles ⇒ 12 minutes
Then, “n” miles ⇒ 40 minutes
Now, by criss cross multiplication we get,
Hence, the ostrich can run 20 miles in 40 minutes
Answer:
1 1/3
Step-by-step explanation:
2/3 x 2/1 = 4/3 = 1 1/3
Answer:
The zeroes in this equation are -5, -4, and 5
Step-by-step explanation:
In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.
r^3 + 4r^2
r^2(r + 4)
Now the second half.
-25r - 100
-25(r + 4)
Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.
(r^2 - 25)(r + 4)
And we can further factor the first parenthesis using the difference of two squares
(r^2 - 25)(r + 4)
(r + 5)(r - 5)(r + 4)
Now that we are fully factored, set each parenthesis equal to 0 and solve for x.
r + 5 = 0
r = -5
r - 5 = 0
r = 5
r + 4 = 0
r = -4
Answer:
242 cm
Step-by-step explanation:
1. Find the scale factor
A scale factor (SF) is the ratio of two corresponding lengths in similar figures.
SF = actual distance/scale distance
If the scale width is 3.8 cm,
SF = 418 cm/3.8 cm = 110
2. Calculate the actual depth
110 = actual depth/2.2 cm
Actual depth = 110 × 2.2 cm = 242 cm
