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1 year ago

Are the graphs of each pair of equations parallel, perpendicular, or neither? x=4 y=4

Mathematics

2 answers:

labwork [276]1 year ago

7 0

Answer:

perpendicular

Step-by-step explanation:

The graph of x = 4 is a vertical line and the graph of y = 3 is a horizontal line.

Vertical and horizontal lines are perpendicular.

Vlad1618 [11]1 year ago

5 0

Both graphs x =4 and y =4 will be perpendicular to each other.

The graph of x = 4 is a vertical line down the Graph scope
The graph of y =4 is a horizontal line side the Graph scope.

Both the Lines will meet exactly at ( 4, 4 ) perpendicularly at each other both of them intersecting at 90 degrees.

Vertical and Horizontal lines are perpendicular to each other (90 Degrees).

Know more about Perpendicular Lines: brainly.com/question/1202004

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Find the quotient of 1+7i/3i in standard form write your answer in standard form

ch4aika [34]

For the first one it would be 10/3 ( 10 over 3 ) and for the second one, it would be 7/13 ( 7 over 13 ) PLUS 4i/13 ( 4i over 13)

3 0

3 years ago

Help please and thank you.

xxTIMURxx [149]

A) sorting the data, you have
.. 8, 10, 14, 15, 18, 22, 22, 30, 33

b) min: 8
.. med: 18
.. max: 33
.. Q1: med of first 4: 12
.. Q3: med of last 4: 26

7 0

3 years ago

Suppose that 23 inches of wire costs 92 cents. At the same rate, how much (in cents) will 19 inches of wire cost?

REY [17]

Answer:

76 cents

Step-by-step explanation:

23 inches = 92 cents

1 inches = 92 ÷ 23

= 4 cents

19 inches = 19 × 4

= 76

5 0

2 years ago

Mr. Walker asked his students to use the associative property to find an expression that is equivalent to (13 + 15 + 20) + (20 +

ozzi

HERES THE ANSWER AND EXPLINATION

⇒Associative property of Addition is applied for three real numbers.For, any three real numbers, A, B and C
≡A+B+C=A+(B+C)=(A+B)+C=(A+C)+B→→→Associative Property of Addition
that is , we can add any two numbers first and then the third number with them.
⇒Also, Commutative Property of Addition of two numbers says that for any two numbers , A and B
≡A+B=B+A
We have to find equivalent expression using Associative Property of the sum of set of three numbers
→→(13+15+20)+(20+47+18)
Answer Written by Jerry
→(20+13+15)+(20+47+18)
Answer Written by Layla
→(20+47+18)+(13+15+20)
The Expression Written by Keith and Melinda is Incorrect,because they haven't used the bracket Properly, as associative property says that you can add any two numbers first and then the third number among three numbers.
→→Number of Students who has applied the Associative property Correctly
Option B ⇒Two(Jerry, Layla)

8 0

3 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes