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Andre45 [30]
2 years ago
7

Describe the faces, edges, verticals of each three dimensional figure. Then identify it.

Mathematics
1 answer:
EastWind [94]2 years ago
6 0

When you have to describe a 3D shape you have to keep the following definitions in mind:

<em>1. The face of a 3D shape is a flat surface.</em>

The shape on the picture has 3 rectangular faces and 2 triangular faces, a total of 5 faces.

<em />

<em>2. The edge is where two faces meet.</em>

For the shape on the picture, there are 3 edges, where the rectangular faces meet each other, and then three edges where the rectangular faces meet each of the triangular faces, this shape has a total of 9 edges.

<em>3. The vertex is a corner, where the edges meet.</em>

There are three vertices on each end of the shape, so it has a total of 6 vertices.

A shape that has 5 faces, 9 edges, and 6 vertices is a triangular prism.

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2/3 + x = 3 im doing this cuss its too short but thats the question
aliina [53]

This is an easy one.

first you move 2/3 to the other side

x=3-2/3

so you get

x=1/3

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3 years ago
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Find the median and the mode of the data.
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Answer:

Median: 8

Mode: 7

I believe this is correct.

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Maggie has a container in the shape of a right prism . The formula for its surface area is SA = Ph + 2B solve for h.
8090 [49]

Answer:

The choose first.

h =  \frac{SA - 2B}{P}

Step-by-step explanation:

SA = Ph + 2B \\  \\ Ph = SA - 2B \\  \\ h =  \frac{SA - 2B}{P}

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3 years ago
Find the value of x and y in the rhombus.
Inga [223]

Answer:

x = 10, y = 13

Step-by-step explanation:

Because EYD is 70, then FEY is also 70. Both triangles are identical.

This means:

45 + 70 + 7x - 5 = 180

7x = 70

x = 10

EFY and EDY are identical and this means:

7x - 5 = 5y

7*10 - 5 = 5y

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5 0
4 years ago
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More than three-quarters of the nation’s colleges and universities now offer online classes, and about 23% of college graduates
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Answer:

0.1997 or 19.97%

Step-by-step explanation:

Have taken course online (H) = 23%

Have NOT taken course online (N) = 77%

Have taken course online and don't believe they provide same value (H&D) = 61%

Have NOT taken course online and don't believe they provide same value (N&D) = 73%

The probability that a student has taken a course online given that she does not believe that online courses provide the same educational value as one taken in person is;

P(H|D)=\frac{P(H)*P(H\&D)}{P(H)*P(H\&D)+P(N)*P(N\&D)}\\P(H|D)=\frac{0.23*0.61}{0.23*0.61+0.77*0.73}\\P(H|D)=0.1997

There is a 0.1997 or 19.97% chance that she has taken an online course before.

3 0
4 years ago
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