With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
Step-by-step explanation:
Add like terms: -10x and x which is equal to -9x. the equation is -9x-76=149 then add 76. the 76s cancel out. add 76 on the other side. it will be -9x=225. U then divide by -9. the -9s cancel out. on the other 225/-9=25. So x=-25 as the answer
Here you go! You actually said p(8) twice so I thought you meant Q(8). Please if the equations are wrong update me with the right equation
The awnser should be either 6 or 20