Answer:
constant acceleration of 9.81 m/s^2 against the weight of the person standing in spaceship.
Explanation:
- At earth surface we would feel a gravitational pull of g = 9.81 m/s^2 downwards.
- For anyone on spaceship to feel the same pull the spaceship needs to accelerate upwards at a constant acceleration of a = 9.81 m/s^2.
- The effect of "weightlessness" is removed such that the contact force between the person on the space-ship and the person him or herself is equal to the apparent weight of the person.
- If the spaceship accelerates constantly at 9.81 m/s^2, the apparent weight of the person would equal the actual weight on earth.
Yes I think because if they swap with each other there would still be magnetic pulls from the same locations
Answer: it reaches 50 feet :)
Explanation:
30+20=50
Answer:
B. surface zone
Explanation:
I got c wrong on the unit test review.
