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Mamont248 [21]
1 year ago
13

Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in

the account after 10 years
Mathematics
1 answer:
romanna [79]1 year ago
4 0

This problem is about componded interest. The formula for compounded interest is:

\begin{gathered} \text{Amount}=\text{Initial}\cdot(1+r)^t \\ \text{Where,} \\ \text{Amount is the total acumulative at time t.} \\ \text{Initial is the initial amount, at t=0} \\ r\text{ is the interest in decimal number.} \\ t\text{ is the time accordingly the interest, in this case is in years.} \end{gathered}

In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}

The amount after 10 years is 573.26.

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Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
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Answer:

C = 60pi cm or approximately 188.4 cm

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

C = 2* pi * 30

C = 60 pi

We can approximate pi by 3.14

C  is approximately 60*3.14 or 188.4

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Step-by-step explanation:

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in jacks class, 18 of the students are y'all and 10 are short. in Michael class 54 students are tall and 30 students are short w
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Answer:

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Step-by-step explanation:

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54/30 = 1.8

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