A garrison of 60 men had provisions for 90 days. If 15 men left the garrison. how long would the provisions last?

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

7 0

Answer: 36 days

Step-by-step explanation:

60-15=45

45 men = 36 days

PLS MARK BRAINLIEST

WARRIOR [948]2 years ago

5 0

The answers is 36 days

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in this triangle, what is the value of x? Enter your answer, rounded to the nearest tenth, in the box. x = A right triangle with

Marat540 [252]

Answer:

56.7°

Step-by-step explanation:

We solve this above question using the Trigonometric function of Sine

sin x = Opposite side/Hypotenuse

Opposite = 66mm

Hypotenuse = 79 mm

sin x = 66/79

x =arc sin(66/79)

x = arcsin(0.8354430379746836)

x = 56.661998553°

Approximately = 56.7°

8 0

3 years ago

Read 2 more answers

No one has answered this one

krek1111 [17]

Answer:

$\displaystyle x = \frac{25\sqrt{2}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 45°

Adjacent Leg = 25

Hypotenuse = x

Step 2: Solve for x

Substitute in variables [cosine]: $\displaystyle cos(45^\circ) = \frac{x}{25}$
[Multiplication Property of Equality] Multiply 25 on both sides: $\displaystyle 25cos(45^\circ) = x$
Rewrite: $\displaystyle x = 25cos(45^\circ)$
Evaluate: $\displaystyle x = \frac{25\sqrt{2}}{2}$