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Aliun [14]
1 year ago
11

2+2=??? PLEASE ANSWER

Mathematics
2 answers:
Dvinal [7]1 year ago
4 0

Answer 4

Step-by-step explanation:

kati45 [8]1 year ago
4 0

Answer:

4

Step-by-step explanation:

2+2=4

just bring out 2 finger on one hand and bring another 2 finger on the other hand and count the together

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MZJ and m M are base angles of isosceles trapezoid JKLM. If mZJ = 18x + 8 and m_M=11x + 15 find m2K.
maxonik [38]

The question is incomplete. Here is the complete question.

m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.

If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.

A. 1

B. 154

C. 77

D. 26

Answer: B. m∠K = 154

Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.

Related to internal angles, angles of the base are equal and opposite angles are supplementary.

In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:

18x + 8 = 11x + 15

7x = 7

x = 1

Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:

m∠J = 18(1) + 8

m∠J = 26

m∠K + m∠J = 180

m∠K + 26 = 180

m∠K = 154

The angle m∠K is 154°

7 0
3 years ago
How do you solve 9x-7= -7 for 2 step equations?
Alinara [238K]
You add +7 to both sides and then divide by 9 to get the x alone.
8 0
3 years ago
Read 2 more answers
10) Determine which of the following are functions. 11) What are the domain and range of the following relation?
Sauron [17]

Answer:

10) The first 2 on the left are functions and the one on the top right is a function, but the bottom right is not.

11) Domain = (2, 8, -1, 0) Range = (5, -2, 4, 5)

3 0
3 years ago
Image on straight line graphs- please help ASAP
MissTica
Plug in (7, 12) for x and y in the equation.

12 = 2(7) + 1
12 = 14 + 1
12 ≠ 15 

Therefore, (7, 12) is not on the straight line equation. 
6 0
3 years ago
Please help me. these problems<br>​
jeyben [28]

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Step-by-step explanation:

You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

3 0
3 years ago
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