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Effectus [21]
2 years ago
7

Which line is perpendicular to the line 5y-2x = 3​

Mathematics
1 answer:
Anni [7]2 years ago
7 0

The equation of the line is y = (5/2)x + 13/2

<h3>Why is the equation of a line?</h3>

Y = a, where an is the y-coordinate of the line's points, is the equation for lines that are horizontal or parallel to the X-axis. A straight line that is vertical or parallel to the Y-axis has the equation x = a, where an is the x-coordinate of each point along the line.

<h3>How do you solve an equation of a line?</h3>

Recognize the slope.

Decide on the point.

In the point-slope form, y y 1 = m (x x 1), substitute the values. y − y 1 = m (x − x 1) .

Slope-intercept form should be used to write the equation.

Rearrange the equation for a single y on one side to account for the gradient:

Step one is 5y = -2x - 3, followed by y = -(2/5)x - (3/5)

The x coefficient of the gradient is -(2/5), thus the perpendicular will be 5/2, which is its reciprocal in the negative.

Therefore, we need a line with a 5/2 gradient that goes across (-1,4).

It should start out as y = (5/2)x...

When we look at (-1,4), the y should be -(5/2), but because it is 4, we must add 13/2 to the equation to make it true.

y = (5/2)x + 13/2

This may be changed to -(5/2)x + y = 13/2 and then -5x + 2y = 13 if desired.

To find the equation of line  click the following link:-

brainly.com/question/18831322

#SPJ1

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