Question

mean difference is t for The Standard deliaftor of a Sample taken from Population A is 17.6 for a Sample of 25. The Standard deviation of a Sample taken from Population B is 21.2 for a sample of 30. The Standard deviation of the Sample mean difference is

Answer 1

Answer:

The standard deviation of a mean difference = 5.23

Explanation:

Given:

Standard deviation of a sample taken from population A = 17.6

the number of samples = 25

Standard deviation of a sample taken from population B = 21.1

the number of samples = 30

To find:

the standard deviation of the mean difference

The standard deviation of a mean difference is given as:

$\begin{gathered} \sigma\text{ = }\sqrt{\frac{\sigma_{A^2}}{n_A}+\frac{\sigma_B^2}{n_B}} \\ \sigma\text{ = standard deviation of the sample mean difference} \end{gathered}$$\begin{gathered} \sigma\text{ = }\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}} \\ \\ \sigma\text{ = }\sqrt{12.3904+14.9813} \\ \\ \sigma\text{ = }\sqrt{27.3717} \\ \\ \sigma\text{ = 5.23} \end{gathered}$

The standard deviation of a mean difference = 5.23