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goldfiish [28.3K]
1 year ago
5

a culture of bacteria starts with 505050 bacteria and increases exponentially. the relationship between bbb, the number of bacte

ria in the culture, and ddd, the elapsed time, in days, is modeled by the following equation. b
Mathematics
1 answer:
lisabon 2012 [21]1 year ago
6 0

In 9 days, the number of bacteria in the culture will reach 800,000.

  • A process called exponential growth sees a rise in quantity over time. It happens when a quantity's instantaneous rate of change with respect to time is equal to the quantity itself.
  • B = 50[10^(d/2)]
  • Small, single-celled creatures called bacteria exist. Nearly all areas of the world are home to bacteria, which are essential to its ecosystems.
  • A microbiological culture, also known as a microbial culture, is a technique for growing microbial organisms in a controlled laboratory environment while allowing them to reproduce in a predefined culture medium. In molecular biology, microbial cultures are fundamental diagnostic techniques that are employed as research tools.
  • We want to find the number of days to reach 800,000 bacteria in the culture.
  • 800000 = 50[10^(d/2)]
  • 16000 = 10^(d/2)
  • d/2 = log_{10} 16000
  • d/2 = 4.204
  • d = 8.408
  • d = 9 days

To learn more about exponential growth, visit :

brainly.com/question/2193820

#SPJ4

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Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

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Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, P = p × (1-\dfrac{\textrm r}{100})^{\textrm t}

Or, 8200 = 10225 × (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, \dfrac{8200}{10225} =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, 0.80195 =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

<u>Taking power \dfrac{1}{6} both side</u>

So, (0.80195 )^{\frac{1}{6}} = ((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}

Or, 0.9638 = 1 - \dfrac{r}{100}

Or,  \dfrac{r}{100} = 1 - 0.9638

Or,  \dfrac{r}{100} = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

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