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Mademuasel [1]
1 year ago
6

Three-tenths times two-tenths

Mathematics
2 answers:
iVinArrow [24]1 year ago
4 0
5:10 5;10 56855543678888
Flura [38]1 year ago
3 0
The answer is 3/50 or 0.06
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Find a cubic polynomial whose zeros are 1/2,1 and -3.
Alexxx [7]

Answer:

2x³+3x²-8x+3

Step-by-step explanation:

So we know x=½,x=1 and x=-3

Then (2x-1)(x-1)(x+3) are the factors

(2x-1)[(x²+3x-x-3)]

(2x-1)[(x²+2x-3)]

2x³+4x²-6x-x²-2x+3

2x³+3x²-8x+3

5 0
2 years ago
Im being timed so uhh help please
Jobisdone [24]
The answer to the following equation is the first one.
3 0
3 years ago
Read 2 more answers
Which equation represents the same line as the points in the table
vodomira [7]

Answer:

y=\frac{-3}{4} x+2

Step-by-step explanation:

First, we can find the slope using the slope equation and two of the points.

Slope equation:

m=\frac{y2-y1}{x2-x1}

I'm going to use the first two points just so I can avoid the fraction... Substitute the x and y values into the equation.

m=\frac{2-5}{0--4}

Simplify:

m=\frac{-3}{4}

Now that we have the slope, all we need is the y-intercept. Luckily, it gives it to us in the table. The x value of y-intercepts will always be 0. Looking at the table, we see that the point where x=0 is (0,2). Thus, the y-intercept is 2. Your final equation is

y=\frac{-3}{4} x+2

7 0
3 years ago
Read 2 more answers
The radius of a circle is 3 meters. What is the circle's circumference?<br> r=3 m<br> Use 3.14 for .
Sunny_sXe [5.5K]
The answer would be 18.84
7 0
3 years ago
Please help me with these questions
Scrat [10]

3. Answer: y = 4

<u>Step-by-step explanation:</u>

Need to find the slope (m):

  \dfrac{y_2-y_1}{x_2-x_1}

  \dfrac{4 - 4}{-3-1}

= \dfrac{0}{-4}

= 0

Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 4 = 0(x - 1)

y - 4 = 0

y      = 4

********************************************************************

4. Answer: \bold{y = \dfrac{2}{3}x + 3}

<u>Step-by-step explanation:</u>

 y - y_1 = m(x - x_1)

 y - 1 = \dfrac{2}{3}(x - (-3))

 y - 1 = \dfrac{2}{3}(x + 3)

 y - 1 = \dfrac{2}{3}x + 2

 y = \dfrac{2}{3}x + 3


3 0
3 years ago
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