Answer:

Step-by-step explanation:
<h3>Arithmetic sequence:</h3>

6th term is 14 ⇒ 
a + (6 - 1)d = 14
a + 5d = 14 --------------(I)
14th term is 6 ⇒
a + (14-1)d = 6
a + 13d = 6 ----------------(II)
Subtract equation (II) from equation(I)
(I) a + 5d = 14
(II) a + 13d = 6
<u>- - -</u>
-8d = 8
d = 8 ÷(-8)

Plugin d = -1 in equation (I)
a + 5(-1) = 14
a -5 = 14
a = 14 + 5
20th term:

= 19 - 19

Answer:c- sixty nine hundredths
Step-by-step explanation:
three tenths can be expressed in decimal as 3/10
thirty nine hundredths can be expressed in decimal as 39/100
Therefore the sum of three tenths plus thirty nine hundredths equals
3/10 +39/100
We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator
then 100 divided by 10 multiplied by 3 +100 divided by 100 multiplied by 39 as illustrated below gives the answer
3/10 +39/100
=30+39/100
=69/100= sixty nine hundredths
Answer:
x = 7/2 or x = -8/3
Step-by-step explanation:
Solve for x over the real numbers:
6 x^2 - 5 x = 56
Divide both sides by 6:
x^2 - (5 x)/6 = 28/3
Add 25/144 to both sides:
x^2 - (5 x)/6 + 25/144 = 1369/144
Write the left hand side as a square:
(x - 5/12)^2 = 1369/144
Take the square root of both sides:
x - 5/12 = 37/12 or x - 5/12 = -37/12
Add 5/12 to both sides:
x = 7/2 or x - 5/12 = -37/12
Add 5/12 to both sides:
Answer: x = 7/2 or x = -8/3
Answer: a is your answer hope this helped
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Step-by-step explanation:
Answer:
The inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.
Step-by-step explanation:
For the function
, Find 
For finding inverse of x,
First let:

Now replace x with y and y with x

Now, solve for y
Taking 5th square root on both sides
![\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3D%5Csqrt%5B5%5D%7B%28y%2B7%29%5E5%7D%5C%5C%5Csqrt%5B5%5D%7Bx%7D%3Dy%2B7%5C%5C%3D%3E%20y%2B7%3D%5Csqrt%5B5%5D%7Bx%7D%5C%5Cy%3D%5Csqrt%5B5%5D%7Bx%7D-7)
Now, replace y with 
![f^{-1} (x)=\sqrt[5]{x}+7](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7)
So, the inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.