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AysviL [449]
1 year ago
10

if 3/4 of one of the acute angles of a right angled tringle is 15-1/4" larger than1/6 of the other,find the acute angels

Mathematics
1 answer:
Vaselesa [24]1 year ago
3 0

The acute angles in the triangle are 16.6 degrees and 73.4 degrees

<h3>How to determine the acute angles?</h3>

From the question, we have:

Triangle type = Right triangle

Let the acute angles be x and y.

So, we have:

3/4x = 1/4 + 1/6y

Multiply through by 12

9x = 3+ 2y

The sum of acute angles in a right triangle is

x + y = 90

Rewrite as

y = 90 - x

Substitute y = 90 - x in 9x = 3+ 2y

9x = 3+ 2(90 - x)

Open the brackets

9x = 3+ 180 - 2x

Evaluate the like terms

11x = 183

Divide by 11

x = 183/11 = 16.6

Substitute x = 183/11 in y = 90 - x

y = 90 - 183/11

Evaluate

y = 807/11 = 73.4

Hence, the acute angles in the triangle are 16.6 degrees and 73.4 degrees

Read more about acute angles at

brainly.com/question/347922

#SPJ1

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3 years ago
Find the value of X. Please help!!
harkovskaia [24]

Answer:

x = 91

Step-by-step explanation:

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5 0
3 years ago
A tank contains 1000L of pure water. Brine that contains 0.02kg of salt per liter enters the tank at a rate of 5L/min. Also, bri
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51.877 kg

Step-by-step explanation:

a

See attachment for calculations

b

The amount of salt in the tank after 4 hours is gotten by simply replacing t in the equation from a, with 4 hours. Since the t gotten in a above is in minutes, we'd convert hours to minute as well. If we do that, we have

t = 4 hours = 4 * 60 minutes = 240 minutes

y = 160/3 (1 - e^((-3 * 240)/200))

y = 160/3 (1 - e^(-720/200))

y = 160/3 (1 - 0.0273)

y = 160/3 (0.9727)

y = 51.877 kg

Therefore, the amount of salt in the tank after 4 hours is 51.877 kg

3 0
3 years ago
Solve the literal equation for y.<br> 4x - 2y = 10
MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

3 0
2 years ago
I have 47 nickels and dimes worth $4.20. How many of each type of coin do I have?
soldi70 [24.7K]

Answer:

37 dimes and 10 nickels

Step-by-step explanation:

let d = # dimes

let n = # nickels

we can set up a system of equations:

n + d = 47

.05n + .10d = 4.2

if we solve the first equation for 'n' we get:  

n = 47-d

now we can substitute this in for 'n' in the second equation:

.05(47-d) + .10d = 4.2

2.35 - .05d + .10d = 4.2

2.35 + .05d = 4.2

subtract 2.35 from each side to get:

.05d = 1.85

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if d+n = 47 and d=37 then n = 10

Check:

.05(10) + .1(37) should equal 4.2

.50 + 3.7 = 4.2  [It Checks Out]

6 0
2 years ago
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