Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:
In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:
If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:
61.84%
Step-by-step explanation:
Let the cost of the box be x. Since the price of the box and the pen is Rs 80, the pen's price can be represented as 80 - x. The box is sold at a ten percent profit, and an added ten percent is equal to 1.1. Therefore, the price the box sells at is 1.1(x). A 20% loss is the same a keeping 80% or multiplying by 0.8. This means the pen sold at 0.8(80 - x). Now, we are given the box went for Rs 28 more than the pen, so we can create an equation:
1.1x = 0.8(80 - x) + 28
We can simplify and solve:
1.1x = 64 - 0.8x + 28
1.9x = 92
x = 92/1.9
x = 920/19
The cost of the box after the increase would be 1.1(920/19) and the pen would be 0.8(80 - 920/19).
The sum of these two can be written as a percent x of 80.
80x = 0.8(80 - 920/19) + 1.1(920/19)
80x = 64 - 0.8(920/19) + 1.1(920/9)
80x = 64 - 0.3(920/19)
80x = 64 - 276/19
80x = 940/19
x = 940/1520
x = 0.6184
This is 61.84%
Answer:
the answer is 798 + 789 mawdgghhji the same time as the work of the Maroons
A. For y= 2x-1, the slope is 2 and the y intercept is -1. Therefore, we should first plot (0,-1). From there, for each increment of x, increase y by 2. For y= 4x-5, the slope is 4 and the y ntercelt is -5. Therefore we should plot (0,-5) and plot an increase of 4 on the y axis per increase of 1 on the x axis. The solution is where the lines cross.
B. (2,3)
The Answer is
X= -1
Y= -5/4
