Step-by-step explanation:
To solve an inequality use the following steps: Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions. Step 2 Simplify by combining like terms on each side of the inequality. Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.
Answer: 5x3 + x2 - 2x + 5
Make sure to combine like terms and watch out for if it’s subtraction or addition.
Answer:
<h2>D. (-2, 4)</h2>
Step-by-step explanation:
Put the coordinates of the points and check the equality.
2x + 3y = 8
A. (1, 4) → x = 1, y = 4
2(1) + 3(4) = 2 + 12 = 14 ≠ 8
B. (2, 2) → x = 2, y = 2
2(2) + 3(2) = 4 + 6 = 10 ≠ 8
C. (-1, 3) → x = -1, y = 3
2(-1) + 3(3) = -2 + 9 = 7 ≠ 8
D. (-2, 4) → x = -2, y = 4
2(-2) + 3(4) = -4 + 12 = 8 CORRECT
Answer:
The number of times over the Weekend that:
Ashley watched TV = x = 12 hours
Gabby watched TV = y = 6 hours
Step-by-step explanation:
Let us represent:
The number of times
Ashley watched TV = x
Gabby watched TV = y
Together, Ashley and Gabby watched a total of 14 hours of television over the weekend.
= x + y = 14..... Equation 1
x = 14 - y
Ashley watched 6 times as many hours as Gabby.
x = 6y
Using substitution method
We substitute 14 - y for x
14 - y = 6y
14 = 6y + y
14 = 7y
y = 14/7
y = 2 hours
Solving for x
x = 14 - y
x = 14 - 2
x = 12 hours
Therefore:
The number of times over the Weekend that:
Ashley watched TV = x = 12 hours
Gabby watched TV = y = 6 hours
Answer:
in both cases
Step-by-step explanation:
See attachment for complete question.
From the attachment, we have the following given parameters
Green Section: Dimension: x by 2
Orange Section: Dimension: 2 by 
Purple Section: Dimension: 3 by (x +
)
Solving (a): Area of the flag as a sum of each section
We simply calculate the area of each section.

For the green section;


For the orange section


For the purple section



Total Area = Sum of the above areas

Collect Like Terms




Solving (b): Area of the flag as a product
From the attachment,







Take LCM
