The equation of a line perpendicular to y = 3x - 8 which contains the point (3, -2) is y=-1/3 x-1.
The given line equation is y = 3x - 8 and the coordinate point is (3, -2).
<h3>What is slope of a line?</h3>
The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The slope of a line y = 3x - 8 is m=3.
The slope of a line perpendicular to given line is m1=-1/m2 = -1/3
Now, put m=-1/3 and (3, -2) in y=mx+c, we get
-2=-1/3(3)+c
⇒ -2 = -1+c
⇒ c=-1
Substitute, m=-1/3 and c=-1 in y=mx+c, we get
y=-1/3 x-1
Therefore, the equation of a line perpendicular to y = 3x - 8 which contains the point (3, -2) is y=-1/3 x-1.
To learn more about the slope of a line visit:
brainly.com/question/14511992.
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