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1 year ago

2+32 + 3 + 5 + 5 + 5

Mathematics

1 answer:

Sergeu [11.5K]1 year ago

4 0

Solution

We have the following expression:

2+32+3+5+5+5

And we can do this:

34 +3+5+5+5

37 + 5 +5 +5

42 +5+5

42+10 =52

Finala answer : 52

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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = e−4x, [0, 2] Yes, it does not m

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(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.

(b) $c =0.51995$

Step-by-step explanation:

Given

$f(x) = e^{-4x};\ [0,2]$

Solving (a); Does the function satisfy M.V.T on the given interval

We have:

$f(x) = e^{-4x};\ [0,2]$

The above function is an exponential function, and it is differentiable and continuous everywhere

Solving (b): The value of c

To do this, we use:

$f'(c) = \frac{f(b) - f(a)}{b - a}$

In this case:

$[a,b] = [0,2]$

So, we have:

$f'(c) = \frac{f(2) - f(0)}{2 - 0}$

$f'(c) = \frac{f(2) - f(0)}{2}$

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$f'(c) = \frac{-0.99966453738}{2}$

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This implies that:

$f'(c) = -4e^{-4c}$

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$e^{-4c} =\frac{-0.4998}{-4}$

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$\ln(e^{-4c}) =\ln(0.12495)$

$\ln(e^{-4c}) =-2.0798$

Apply law of natural logarithm

$\ln(e^{ax}) =ax$

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$-4c =-2.0798$

Solve for c

$c =\frac{-2.0798}{-4}$

$c =0.51995$

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3 years ago

3.6 (5 x 4) ÷ 3 + 5.0

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3.6 (5 x 4) ÷ 3 + 5.0

use the PEMDAS rule

P - parentheses

E - exponents

M - multiplication

D - division

A - addition

S - subtraction

3.6 (5 x 4) ÷ 3 + 5.0

= 3.6 (20) ÷ 3 + 5.0

= 72 ÷ 3 + 5.0

= 24 + 5.0

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so the final answer would be 29!!

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