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Neko [114]
2 years ago
3

Need help asap!!!! give brainleist

Mathematics
1 answer:
Luda [366]2 years ago
7 0

By definition of supplementary angles,  ∠1 + ∠2 = 180°.

and  ∠2 + ∠3 = 180°

Then:

∠1 + ∠2  =  ∠2 + ∠3

Subtracting ∠2 in both sides we get:

∠3 =  ∠1

<h3>How to prove that angles ∠1 and ∠3 have the same measure?</h3>

First, we know that ∠1 and ∠2 are supplementary (two angles are supplementary if their measures adds up to 180°), this means that:

∠1 + ∠2 = 180°

And we also know that ∠2 and ∠3 are supplementary, then:∠2 + ∠3 = 180°

So we have two equations:∠1 + ∠2 = 180°∠2 + ∠3 = 180°

If we take the difference between these equations we will get:

(∠1 + ∠2) - (∠2 + ∠3) = 180° - 180°

Solving this we get:∠1 - ∠3 = 0Then:∠1 = ∠3So we have proven that these angles are equal.

Learn more about supplementary angles:

brainly.com/question/2046046

#SPJ1

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the bowling alley charges a flat rate of $50 for a birthday party plus $4.25 per person. If Emanuel only has $125 to spend. How
Maksim231197 [3]

125 > 50 + 4.25*p

subtract 50 from each side

75 =>4.25p

divide by 4.25

p>17.64

He may invite up to 17 people ( if he doesn't have to pay for himself)

He may invite 16 if he has to pay for himself

3 0
4 years ago
The authors of a paper presented detailed case studies to medical students and to faculty at medical schools. Each participant w
stealth61 [152]

Answer:

0.623

Step-by-step explanation:

We have to find the probability that a diagnosis is correct given that confidence in the correctness of diagnosis is high i.e.P(C/H)=?

Using Bayes' theorem the probability can be computed as

P(C/H)=\frac{P(C)P(H/C)}{P(C)P(H/C)+P(I)P(H/I)}

We are given that

P(C) = 0.262 , P(H/C) = 0.344 , P(I) = 0.738  and P(H/I) = 0.074.

So,

P(C/H)=\frac{0.262(0.344)}{0.262(0.344)+0.738(0.074)}

P(C/H)=\frac{0.0901}{0.0901+0.0546}

P(C/H)=\frac{0.0901}{0.1447}

P(C/H)=0.6227

P(C/H)=0.623 (rounded to three decimal places).

Thus, the probability that a diagnosis is correct given that confidence in the correctness of diagnosis is high is 0.623.

3 0
3 years ago
Help meeèeeeeeeeeeeee​
mamaluj [8]
The answer is B your welcome
3 0
3 years ago
Express as a complex number in a+bi form: 2-10i/-3-7i
pochemuha
\large\begin{array}{l} \mathsf{z=\dfrac{2-10i}{-3-7i}}\\\\\\ \textsf{Multiply and divide by the denominator's conjugate }\mathsf{(-3+7i):}\\\\ \mathsf{z=\dfrac{2-10i}{-3-7i}\cdot \dfrac{-3+7i}{-3+7i}}\\\\ \mathsf{z=\dfrac{(2-10i)\cdot (-3+7i)}{(-3-7i)\cdot (-3+7i)}} \end{array}

\large\begin{array}{l} \textsf{Multiply brackets out:}\\\\ \mathsf{z=\dfrac{(2-10i)\cdot (-3)+(2-10i)\cdot 7i}{(-3-7i)\cdot (-3)+(-3-7i)\cdot 7i}}\\\\ \mathsf{z=\dfrac{-6+30i+14i-70i^2}{9+\,\diagup\!\!\!\!\!\! 21i-\diagup\!\!\!\!\!\! 21i-49i^2}}\qquad\quad\textsf{(but }\mathsf{i^2=-1}\textsf{)}\\\\ \mathsf{z=\dfrac{-6+30i+14i-70\cdot (-1)}{9-49\cdot (-1)}}\\\\ \mathsf{z=\dfrac{-6+44i+70}{9+49}} \end{array}

\large\begin{array}{l} \mathsf{z=\dfrac{-6+70+44i}{58}}\\\\ \mathsf{z=\dfrac{64+44i}{58}}\\\\ \mathsf{z=\dfrac{\diagup\!\!\!\! 2\cdot (32+22i)}{\diagup\!\!\!\! 2\cdot 29}}\\\\ \mathsf{z=\dfrac{32+22i}{29}}\\\\\\ \textsf{Split into two fractions:}\\\\ \mathsf{z=\dfrac{32}{29}+\dfrac{22}{29}\,i} \end{array}


\large\begin{array}{l} \therefore~~\boxed{\begin{array}{c} \mathsf{\dfrac{2-10i}{-3-7i}=\dfrac{32}{29}+\dfrac{22}{29}\,i} \end{array}}\qquad\checkmark\\\\\\ \textsf{which already is in }\mathsf{a+bi}\textsf{ form:}\\\\ \mathsf{a=\dfrac{32}{29}}\textsf{ and }\mathsf{b=\dfrac{22}{9}\,\cdot} \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154166


\large\textsf{I hope it helps.}
</span>
4 0
3 years ago
A triangle has side lengths of 9 cm, 25 cm, and 33 cm. Classify it as acute, obtuse, or right.
miskamm [114]

Answer:

Obtuse.

Step-by-step explanation:

If sides are a b and c, with c the longest:

c^2 = a^2 + b^2 = Right triangle

c^2 < a^2 + b^2 = Acute     ...

c^2 > a^2 + b^2 = Obtuse  ...

33^2 = 1089

25^2 = 625

9^2 = 81

625 + 81 = 706

1089 > 706 so the triangle is obtuse.

5 0
2 years ago
Read 2 more answers
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