Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
8x.......................
Answer:
Deduction in the step-by-step explanation
Step-by-step explanation:
If a P0=50.000 deposit is compound every instant, the ammount in the account can be modeled as:
If you pull out d dollars a year, the equation becomes:
If we derive this equation in terms of t, we have
The first term can be transformed like this:
So replacing in the differential equation, we have
Rearranging
Answer:
D
Step-by-step explanation:
You can infer to the solution of this problem by looking at the choices. Hope this helped :)
