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Shtirlitz [24]
1 year ago
3

if the spring constant of a simple harmonic oscillator is quadrupled, by what factor will the mass of the system need to change

in order for the frequency of the motion to remain the same?
Physics
1 answer:
Dmitry [639]1 year ago
3 0

the mass of the system must be quadrupled

here,

the initial spring constant is K0

the final spring constant , K = 4 * K0

when the frequency remains the same

(1/2*pi) * sqrt(K/m) = (1/2*pi) * sqrt(K0/m0)

K/m = K0 /m0

4 * K0 /m = K0 /m0

m = 4 * m0

the mass of the system must be quadrupled

In classical mechanics, a harmonic oscillator is a system that, when displaced from its equilibrium position, experiences a restoring force F proportional to the displacement x:

where k is a positive constant. If the only force acting on a

system is F, the system is called a simple harmonic oscillator, and it oscillates simply. Sinusoidal oscillation of constant amplitude and constant frequency (independent of amplitude) around the equilibrium point.

A harmonic oscillator is called a damped oscillator if there is also a frictional force (damping) proportional to velocity. Depending on the coefficient of friction, the system can:

Oscillates at a lower frequency than undamped and decreases in amplitude over time (underdamped oscillator). The

damps to its equilibrium position without oscillation (overdamped oscillator).

Learn more about harmonic oscillator here :

brainly.com/question/14616416

#SPJ4

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