In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.
<h3>What is the angle about?</h3>
Note that:
Δ ABC , A = 90
To find length of DA :
Let Δ ACB = x
So Δ ABC = 90 -x
For Δ ABC and ADC:
Δ ADB = Δ ADC (90°)
Δ ABD = Δ DAC (90 - x)
For Δ ABC ≈ ADC:

AD² = BD. CD.
AD²= 9 . 4
AD²= 36
AD = 6
Therefore, In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.
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The area of the triangle is
A = (1/2)bh
= (1/2)(3 ft)(6 ft)
= 9 ft^2
That triangular area is not carpeted, so the carpet area is
72 ft^2 -9 ft^2 = 63 ft^2.
Step-by-step explanation:
=>a+6a=90-12
=>7a=78
=>a=11,14
Answer:
22
Step-by-step explanation:

TIP:
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