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9 months ago

How many times as great is the diameter of a pinhead as the diameter of a cloud-water droplet

Mathematics

1 answer:

Ulleksa [173]9 months ago

5 0

Given:

The diameter of cloud-water droplet is

$10^{-5}$

The diameter of pinhead is 0.001.

Explanation:

Divide the dimater of cloud-water droplet by dimater of pinhead to determine the times as great is the diameter of a pinhead as the diameter of a cloud-water droplet .

$\begin{gathered} a=\frac{0.001}{10^{-5}} \\ =0.001\cdot10^5 \\ =100 \end{gathered}$

So diameter of a pin-head is 100 times the diameter of water-droplet.

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If f(x)= 3x + 4, then what is f(-2)

iren [92.7K]

Answer:

f ( - 2 ) = - 2

Step-by-step explanation:

Step 1:

f ( x ) = 3x + 4 Equation

Step 2:

f ( - 2 ) = 3 ( - 2 ) + 4 Input x value

Step 3:

f ( - 2 ) = - 6 + 4 Combine Like Terms

Answer:

f ( - 2 ) = - 2 Combine Like Terms

Hope This Helps :)

6 0

2 years ago

Kendra has a painting canvas that is 20 inches wide by 37 inches high. She painted a red rose, which covered 50% of the canvas.

uysha [10]

The total area is:
A = (20) * (37)
A = 740 in ^ 2
We can make the following rule of three:
740in ^ 2 -----> 100%
x --------------> 50%
Clearing x we have:
x = (50/100) * (740)
x = 370 in ^ 2
Answer:
the area of the canvas which was covered by the red rose was:
x = 370 in ^ 2

6 0

2 years ago

brian makes an investment in his company’s stock . what does the stock chart say about the stock price today? The down arrow ind

Ivan

Answer:50$ and 2

Step-by-step explanation:

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1 year ago

Thomas earns 15 mowing lawns over 3 days. How much money would he earn in 4 days if he earned the same amount every day

gladu [14]

Answer: 20 Dollars

Step-by-step explanation:

15 divided by 3 is 5. So, then multiply 4x5 and that equals 20

7 0

2 years ago

Read 2 more answers

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, $n = 11$ .

Therefore, the middle term = $\frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term$

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, 24, 25, 26

Here also, $n=5$ . So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, 47, 48, 50

Here also, $n=5$ . So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

7 0

2 years ago