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laila [671]
1 year ago
13

How many times as great is the diameter of a pinhead as the diameter of a cloud-water droplet

Mathematics
1 answer:
Ulleksa [173]1 year ago
5 0

Given:

The diameter of cloud-water droplet is

10^{-5}

The diameter of pinhead is 0.001.

Explanation:

Divide the dimater of cloud-water droplet by dimater of pinhead to determine the times as great is the diameter of a pinhead as the diameter of a cloud-water droplet .

\begin{gathered} a=\frac{0.001}{10^{-5}} \\ =0.001\cdot10^5 \\ =100 \end{gathered}

So diameter of a pin-head is 100 times the diameter of water-droplet.

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What is the answer to -10x-1=11-9x
Harman [31]
-10x-1 = 11 -9x
+10x +10x
-1 = 11 + x
-11 -11
-12 = x

x= -12
5 0
3 years ago
Read 2 more answers
Kunicki uses a medium and a large measuring cup to measure the ingredients to make his famous Buttery Oatmeal Raisin Cookies. He
Nonamiya [84]

Answer:

L = 16oz

M = 12oz

S = 8oz

Step-by-step explanation:

8 large equal to 128oz ( 8 x 16 = 128 )

4 medium equal to 48oz ( 4 x 12 = 48

4 large equal to 64oz ( 4 x 16 = 64

12 medium equal to 144oz ( 12 x 12 = 144 )

Total of oz equal 384oz

384 - 80 = 304/80 = 3.8

3 more bowl of 80oz and 5 Mcup and 1/2 Scup

4 0
3 years ago
27.) A customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. The total bill was $53.50. Write and
Talja [164]

Answer:

c) The equation to find the price of each shrub is    $53.50 = 4 p + $17.50

The cost of 1 shrub = p =  $ 9.00

Step-by-step explanation:

The total number of shrubs purchased = 4

The price paid for potting soil = $17.50

The total bill of purchase = $53.50

Let us assume the cost of 1 shrub   = $p

The total amount spent of 4 shrubs = 4 x ( The price of each shrub)  =  4 p

TOTAL BILL = The amount paid for 4 shrubs +  AMOUNT paid for SOIL

⇒ $53.50 = 4 p + $17.50

Now. solving for p, we get:

53.50 - 17.50  = 4  p

or, 3 6  = 4 p

or, p = 36/4 = 9

or, p = 9

Hence, the cost of each shrub = $9

3 0
3 years ago
The ratio of the corresponding side lengths is 10:7 What is the ratio of the areas?
algol [13]
100 to 49. Because area is units squared, and it is finding by multiplying the side lengths, you would simply square the ratio.
4 0
4 years ago
Please help fast <br>need it by today
KiRa [710]
6. It is asking you to find the surface area for this one:

1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters

The volume of the cylinder has to be 0.0154m^3.

V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m

Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2

Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.

C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2

Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2

You will need 0.47m^2 of sheet metal to make this cylinder.

7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.

Everything:
Watch out for units, since the diameter is in mm and the length is in cm.

r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3

Graphite:

r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3

5.34 - 0.11 = 5.23cm^3

8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:

r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3

153.94*250 = 38484.51cm^3 of soup needed.

I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day
3 0
3 years ago
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