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NISA [10]
2 years ago
12

Lines CD and DE are tangent to circle A, as shown below: Lines CD and DE are tangent to circle A and intersect at point D. Arc C

E measures 125 degrees. Point B lies on circle A. If arc CE is 125°, what is the measure of ∠CDE? 55° 62.5° 117.5° 125°
Mathematics
1 answer:
melamori03 [73]2 years ago
5 0

The measure of angle CDE ( ∠CDE) is 55°. The correct option is the first option  55°

<h3>Calculating the measure of the angle formed by two tangents</h3>

From the question, we are to determine the measure of angle CDE.

From one of the circle theorems, we have that

"<em>The measure of the angle formed by two tangents that intersect at a point outside a circle is equal to one-half the positive difference of the measures of the intercepted arcs</em>"

Thus,

m ∠CDE = 1/2(measure of arc CBE - measure of arc CE)

From the given information,

Measure of arc CE = 125°

Then,

Measure of arc CBE = 360° - 125°

Measure of arc CBE = 235°

Therefore,

m ∠CDE = 1/2(235° - 125°)

m ∠CDE = 1/2(110°)

m ∠CDE = 55°

Hence, the measure of ∠CDE is 55°

Learn more on Calculating the measure of the angle formed by two tangents here: brainly.com/question/9143293

#SPJ1

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