Answer:
x = -8
y = -6
Step-by-step explanation:
y = -2x - 22
y = x + 2
x + 2 = -2x - 22
x + 2x = -22 - 2
3x = -24
x = -24 : 3
x= -8
y = -8 + 2
y = -6
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer: 1500
Step-by-step explanation:
5 m/s in 0 m/s in 1 sec
so its 1500
Step-by-step explanation:
( 0,-4) that the answer