Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which
1 answer:
Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:
1. The word "more" indicates an Addition.
2. The word "times" indicates Multiplication.
Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:
Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:
Hence, the answer is:
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the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then
when will it reach the ground level? let's set s(t) = 0
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the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then
when will it reach the ground level? let's set s(t) = 0
part B) check the picture below