Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which
1 answer:
Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:
1. The word "more" indicates an Addition.
2. The word "times" indicates Multiplication.
Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:
Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:
Hence, the answer is:
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<h3>Zeros of function are 
</h3>
<em><u>Solution:</u></em>
<em><u>We have to find the zeros of the function</u></em>
Find the zeros of function:
We have two zeros
Thus zeros of function are
Answer:
Step-by-step explanation:
In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)
This diagram will help us visualize the problem better.
So we start by determining what data we already know:
Height=6in
Diameter=3.8in
Radius = 1.9 in (because the radius is half the length of the diameter)
The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:
which yields:
with this information we can start solving the problem.
First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:
where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.
Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:
or
We can now take the derivative to this formula so we get:
Which simplifies to:
We can now substitute the data provided by the problem to get:
which yields:
