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mr Goodwill [35]
1 year ago
13

Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which

is the weight of Gail’s dog.
Mathematics
1 answer:
emmasim [6.3K]1 year ago
7 0

Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:

1. The word "more" indicates an Addition.

2. The word "times" indicates Multiplication.

Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:

5g

Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:

5g+6

Hence, the answer is:

5g+6

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Answer:

$39

Step-by-step explanation:

60 x 0.39 = 21

60 - 21 = 39

Kayla bought a necklace on sale for $39.

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one bag of toy animals weigh12 ounces. what is the total weight, in ounces, of the bags of toy animals in one crate
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4 years ago
A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
Naddik [55]

Answer:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

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A tutor charges $5 for each class he takes per day that lasts for an hour. for each additional hour he tutors he charges $3. mat
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Answer:

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