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mr Goodwill [35]
10 months ago
13

Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which

is the weight of Gail’s dog.
Mathematics
1 answer:
emmasim [6.3K]10 months ago
7 0

Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:

1. The word "more" indicates an Addition.

2. The word "times" indicates Multiplication.

Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:

5g

Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:

5g+6

Hence, the answer is:

5g+6

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The ordered pair (-3 , \frac{4}{375} ) is on g(x) ⇒ 1st answer

Step-by-step explanation:

Let us revise the reflection across the axes

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- Change the sign of x

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{-x}

To find the point that lies on g(x) substitute x in g(x) by the x-coordinate of the point if the answer equal to the y-coordinate of the point, then the point lies on it if not then the point does not lie on it

∵ The coordinates of the point are (-3 , \frac{4}{375} )

∴ x = -3 and y = \frac{4}{375}

- Substitute x by -3 in g(x)

∵ g(x)=\frac{1}{6}(\frac{2}{5})^{-x}

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{-(-3)}

∴ g(x)=\frac{1}{6}(\frac{2}{5})^{3}

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∴ g(x)=\frac{1}{6}(\frac{8}{125})

∴ g(x)=\frac{8}{750}

- Divide up and down by 2

∴ g(x)=\frac{4}{375}

∵ The value of g(x) equal to the y-coordinate of the point

∴ The point (-3 , \frac{4}{375} ) lies on g(x)

The ordered pair (-3 , \frac{4}{375} ) is on g(x)

Learn more:

You can learn more about the reflection in brainly.com/question/5017530

#LearnwithBrainly

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