Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog. What algebraic expression could you make to find (g) which
1 answer:
Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:
1. The word "more" indicates an Addition.
2. The word "times" indicates Multiplication.
Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:
Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:
Hence, the answer is:
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Answer:
B. 585
Step-by-step explanation:
A graph of the scatter plot and line of best fit is attached.
The temperature in this problem will be the independent variable, or x. This is because we are assuming that the number of ice cream cones sold depends on the temperature; this means the number of ice cream cones will be the dependent variable, or y.
This means in our graphing calculator, we will enter temperature in the first list and the number of cones in the second.
After drawing the scatter plot, we run the linear regression; we get the values for a and b in our equation, y = ax+b:
a = 5.08
b = 46.59
This gives us the equation y = 5.08x + 46.59.
Entering our temperature, 106, in for x gives us
y = 5.08(106) + 46.59 = 585.07 ≈ 585
