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Serjik [45]
1 year ago
10

3x − 4 > 5 or 2x+1 ≥ 7

Mathematics
2 answers:
Mariulka [41]1 year ago
6 0

Answer:

\boxed{\sf{x > 3 , \quad x\geq 3}}

Step-by-step explanation:

To solve this inequality, isolate the term of x from one side.

3x-4>5 or 2x+1≥7

<h3>1. 3x-4>5</h3>

First, add by 4 from both sides.

\sf{3x-4+4 > 5+4}

Solve.

Add.

5+4=9

\sf{3x > 9}

You divide by 3 from both sides.

3x/3>9/3

Solve.

Divide.

9/3=3

\rightarrow \boxed{\sf{x > 3}}

<h3>2. 2x+1≥7</h3>

First, subtract by 1 from both sides.

\sf{2x+1-1\geq 7-1}

Solve.

Subtract.

7-1=6

2x≥6

Divide by 2 from both sides.

2x/2≥6/2

Solve.

Divide.

6/2=3

\rightarrow \boxed{\sf{x\geq 3}}

Therefore, the correct answer is x>3 and x≥3.

ella [17]1 year ago
4 0

Answer:

x > 3 or x ≥ 3

Explanation:

3x - 4 > 5

3x>9

x > 3

2x+1 ≥ 7

2x ≥ 6

x ≥ 3

<u><em>PLEASE MARK AS BRAINLIEST</em></u>

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