when an overridden method is called from within a subclass, it will always refer to the version of that method defined by the (a
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Answer:
I am writing the program in JAVA and C++
JAVA:
public int createLicenseNum(int customID){ //class that takes the customID as parameter and creates and returns the licenseNum
licenseNum = (100000 * customID) + licenseYear; //licenseNum creation formula
return(licenseNum); }
In C++ :
void DogLicense::CreateLicenseNum(int customID){ //class that takes the customID as parameter and creates the licenseNum
licenseNum = (100000 * customID) + licenseYear; } //licenseNum creation formula
Explanation:
createLicenseNum method takes customID as its parameter. The formula inside the function is:
licenseNum = (100000 * customID) + licenseYear;
This multiplies 100000 to the customID and adds the result to the licenseYear and assigns the result of this whole expression to licenseNum.
For example if the SetYear(2014) means the value of licenseYear is set to 2014 and CreateLicenseNum(777) this statement calls createLicenseNum method by passing 777 value as customID to this function. So this means licenseYear = 2014 and customID = 777
When the CreateLicenseNum function is invoked it computes and returns the value of licenseNum as:
licenseNum = (100000 * customID) + licenseYear;
= (100000 * 777) + 2014
= 77700000 + 2014
licenseNum = 77702014
So the output is:
Dog license: 77702014
To call this function in JAVA:
public class CallDogLicense {
public static void main(String[] args) {//start of main() function
DogLicense dog1 = new DogLicense();//create instance of Dog class
dog1.setYear(2014); // calls setYear passing 2014
dog1.createLicenseNum(777);// calls createLicenseNum passing 777 as customID value
System.out.println("Dog license: " + dog1.getLicenseNum()); //calls getLicenseNum to get the computed licenceNum value
return; } }
Both the programs along with the output are attached as a screenshot.
