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iragen [17]
1 year ago
5

please notice that on the first one there is ( squares dont worry about those please just take them out )

Mathematics
1 answer:
zalisa [80]1 year ago
4 0

By using exponent properties we will see that:

1) The expression is equal to 16.

2) The expression is equal to 4^6, so the correct option is B.

<h3>What is the value of the expression?</h3>

Here we want to solve the expression:

(2^0*4^(-2)*2^3*4^3)/2

Remember the exponent property:

a^x*a^y = a^{x + y}

let's rewrite the numerator:

2^0*4^(-2)*2^3*4^3

= (2^0*2^3)*(4^(-2)*4^3)

= 2^(0 + 3)*(4^(-2 + 3))

= 2^3*4 = 2^3*2*2 = 2^(3 + 1 + 1) = 2^5

Then we can rewrite the expression as:

2^5/2 = 2^4 = 16

b)

(1/4^-3)^2

The negative exponent means that we need to take the inverse:

(1/4^-3)^2 = (4^3)^2 = (4^3)*(4^3) = 4^(3 + 3) = 4^6

So the correct option is B.

Learn more about exponents:

brainly.com/question/847241

#SPJ1

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Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

7 0
2 years ago
I don’t know if this is right, I’m stuck. Help!
STALIN [3.7K]

Answer:

C

Step-by-step explanation:

According to SohCahToa, cosine is adjacent over the hypotenuse.

The adjacent when looking from angle b, is 21.

The hypotenuse of this triangle is 29.

So Cos B=21/29

5 0
3 years ago
Which equation represents a circle with a center at (2, –8) and a radius of 11? (x – 8)2 + (y + 2)2 = 11 (x – 2)² + (y + 8)² = 1
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Answer:The answer B: (x – 2)² + (y + 8)² = 121

Step-by-step explanation:

Just took the test on edge

4 0
4 years ago
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Over the last 3 months, Janet exercised a total of 101 hours. She exercised 4 hours more during the second month than the first
olganol [36]

In 1st month let she exercised h hours

in second month she exercised h+4 hours

in third month she exercised h+4-3=h+1 hours

Now

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NISA [10]

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C

Step-by-step explanation:

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