Question

I need help on a question

Answer 1

Given the figure of a regular pyramid

The base of the pyramid is a hexagon with a side length = 6

The lateral area is 6 times the area of one of the side triangles

So, the side triangle has a base = 6

The height will be:

$\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}$

so, the lateral area =

$6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}$