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finlep [7]
1 year ago
6

The students in Roberto’s school are painting a mural they will be 8 feet by 15 ft. First they make a scale drawing of the mural

with a scale of 2 feet:5 feet.
A- write an equation for the proportional relationship between drawing mural lengths x in feet and mural lengths y in feet.


B- what are the length and width of a scale drawing in feet? Show your work
Mathematics
1 answer:
posledela1 year ago
3 0

A) The equation for the proportional relationship between the drawing of the mural and the actual mural is it is (2/5)th of the actual length and width.

B) The length of the mural in the drawing is 6 feet and the width is 3.2 feet.

<h3>What is the scale factor?</h3>

The scale factor defines how many times more or less two representations are.

Given the actual length of the mural is 15 feet and the width is 8 feet.

Also given the drawing scale and the actual scale is of 2feet:5feet,

Which can be written as that the drawing is of (2/5)th of the actual mural.

∴ The length of the mural in the drawing is (2/5)×15 = 6 feet.

The width of the mural in the drawing is (2/5)×8 = 3/2 feet.

learn more about scale factor here :

brainly.com/question/22312172

#SPJ1

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9966 [12]

Answer:

  72 feet from the shorter pole

Step-by-step explanation:

The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.

The shorter pole height as a fraction of the total pole height is ...

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so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:

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  d = 168·(3/7) = 72

The wire should be anchored 72 feet from the 18 ft pole.

_____

<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

  L = √(18²+x²) + √(24² +(168-x)²)

and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.

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3 years ago
If x/y + y/x = -1 , find the value of x^3 - y^3
marin [14]

Answer:

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Step-by-step explanation:

Multiplying the first equation by xy, we have ...

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Substituting for xy using the first expression we found, this is ...

  x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

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