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tia_tia [17]
2 years ago
14

A sector of a circle has an arc length of π cm and a central angle of π/6 radians. What is the area of the sector?A. 3π cm²B. 2π

cm²C. π cm²D. 5π cm²
Mathematics
1 answer:
inn [45]2 years ago
5 0

Our problem involves the properties and formulas involving a sector.

A sector is a part of a circle it is like a slice of a pie or a cake.

To find the area of a sector we must have its central angle and radius. But in our problem, the central angle is given but there is no sign of radius being given. So first we have to find the radius of our circle.

To find the radius of our circle we can use the given Arc length of the circle. An Arc Length of a Circle (S) is given by the formula:

S=\theta r

Where S is the arc length, θ is the Central angle in radians, and r is the raduis. Since we already have a value for S and θ. We can now find the value of r, or the radius.

\begin{gathered} S=\theta r \\ \pi=\frac{\pi}{6}(r) \\ 6\pi=\pi r \\ 6=r \end{gathered}

Therefore we now know that the radius of the circle is 6 cm.

Now that we know the radius of the circle we can now find its area using the formula:

A=\frac{\theta r^2}{2}

Where A is the area, θ is the central Angle, and r is the radius.

\begin{gathered} A=^{}\frac{\theta r^2}{2} \\ A=\frac{(\frac{\pi}{6})(6)^2}{2} \\ A=\frac{\pi6}{2} \\ A=3\pi \end{gathered}

Therefore the answer is 3π cm². Which is OPTION A.

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A rectangle has a length of 6 feet and a width of 4 feet. The perimeter of the rectangle can be found using the equation =2×6+2×
evablogger [386]

Answer:

The correct answer is perimeter is given by 2 × ( l + w), where l is the length and w is the width of the rectangle.

Step-by-step explanation:

A rectangle has a length of 6 feet and a width of 4 feet. The perimeter of the rectangle can be found using the equation =2×6+2×4.

Let l be the length and w be the width of a rectangle.

Since there four sides of a rectangle, the perimeter is given by adding all the sides.

Therefore perimeter of the rectangle is given by l + l + b + b = 2×l +2×w = 2 × ( l + w).

The equation given by 2 × ( l + w) can also be used to find the perimeter of any given rectangle.

6 0
4 years ago
Find the point on the plane 2x+5y+z=8 that is nearest to​ (2,0,1).
Svetach [21]

Answer:

(2.2, 0.5, 1.1)

Step-by-step explanation:

The parametric equation of the line normal to the plane and through point (2, 0, 1) can be written ...

... L = (2, 0, 1) + t(2, 5, 1)

We want to find the value of t (and the corresponding point) that makes L satisfy the equation of the plane.

... 2(2+2t) +5(0 +5t) +1(1+t) = 8 . . . . . put values from L in for x, y, z in plane

... 5 + 30t = 8 . . . . . simplify

... t = (8 -5)/30 = 0.1 . . . . solve for t (subtract 5, divide by 30)

For this value of t, L is ...

... (2, 0, 1) + 0.1(2, 5, 1) = (2.2, 0.5, 1.1)

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ziro4ka [17]
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The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

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simply subtract 5.8 from 11.0.
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