Use the segment addition postulate to solve for the length of BC, if AC = 16, BC = x + 11, and AB = 3x-7.

The area of a rectangle is 4w - 10 square units.

podryga [215]

Area of rectangle = 2(2w - 5) is the factored form of given expression

Multiplying the length and width of a rectangle, we get the area of the rectangle

Solution:

Given that, area of rectangle is 4w - 10 square units

We have to factor the expression

From given,

Area of rectangle = 4w - 10

Take 2 as common factor

Area of rectangle = 2(2w - 5)

Thus the given expression is factored

The area of rectangle is given as:

$Area\ of\ rectangle = length \times width$

$Area\ of\ rectangle = 2 \times (2w - 5)$

Thus, multiplying the length and width of a rectangle, we get the area of the rectangle

When we multiply 2 with 2w - 5 we get the area of rectangle

From above we can say,

Length = 2 or 2w - 5

Width = 2w - 5 or 2

So when dimensions of rectangle are multiplied we get area of rectangle

3 0

3 years ago

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

4 years ago

Solve for V and U. No work required.

NNADVOKAT [17]

Answer:

v=37 degrees; u=53 degrees

6 0

3 years ago

Does anyone know how to find this I'm studying and me and my family don't understand! I only need help on #17

avanturin [10]

Answer:

4

Step-by-step explanation:

Hi so basically you just convert the inches to decimals so

0.5 x 0.5 x 0.25 = 0.0625

Use a calculator to convert 0.0625 into fraction which is $\frac{1}{16}$

Multiply $\frac{1}{4}$ by 3 = $\frac{1}{64}$

Then multiply $\frac{1}{16}$ by $\frac{1}{64}$ = 4

Soo that was probably very confusing, but I hope it helps! :)

Plz click the Thanks button, I rrly appreciate it!

5 0

4 years ago

Read 2 more answers

A gym all machine contains 23 green gum balls, 52 red gum balls, 34 blue gum balls, 61 yellow gum balls, and 30 pink gum balls.

LenKa [72]

Answer:

26%

Step-by-step explanation:

total gum balls 200

52/200 = x/100

52×100=5200

5200÷200=26

5 0

3 years ago