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KatRina [158]
1 year ago
11

A triangle has side lengths of (q+r)(q+r) centimeters, (5q-10s)(5q−10s) centimeters, and (5s-7r)(5s−7r) centimeters. Which expre

ssion represents the perimeter, in centimeters, of the triangle?
Mathematics
1 answer:
Stolb23 [73]1 year ago
8 0

The expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s

<h3>What is the perimeter?</h3>

The formula for perimeter of a triangle is expressed as;

Perimeter = a + b + c

Where a , b and c are the lengths of its side

  • (q+r)
  • (5q-10s)
  • (5s-7r)

Now, let's substitute the values

Perimeter = (q + r) + (5q - 10s) + (5s - 7r)

expand the bracket

Perimeter = q + r + 5q - 10s + 5s - 7r

collect like terms

Perimeter = q + 5q + r - 7r -10s + 5s

Add like terms

Perimeter = 6q - 6r - 5s

Thus, the expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s

Learn more about perimeter here:

brainly.com/question/24571594

#SPJ1

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Jan spent the day at the mall. She came home with $9.50. She spent $5.25 on earrings and 3 times that amount on a shirt. How muc
ki77a [65]

Answer:

She took $30.50 to the mall originally

Step-by-step explanation:

Let us solve the problem step by step

∵ She spent $5.25 on earrings

∵ The price of the shirt is 3 times the price of the earrings

∴ The price of the shirt = 3 × 5.25 = 15.75

∴ She spent $15.75 on the shirt

Find her total spending in the mall by adding the prices of earrings and the shirt

∴ She spent = 5.25 + 15.75 = 21

∴ She spent $21 on the mall

∵ She came home with $9.50

∵ She spent $21 on the mall

- Add them to find her original amount of money

∴ She took = 21 + 9.50 = 30.50

∴ She took $30.50 to the mall originally

5 0
3 years ago
(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

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cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

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erastova [34]
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Fraction: 22/7
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MAXImum [283]

Answer:

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Step-by-step explanation:

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