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fiasKO [112]
1 year ago
11

HELPPPPPP HELPPPPP PLEASE!!!!!!

Mathematics
1 answer:
blondinia [14]1 year ago
6 0

Answer:

D

Step-by-step explanation:

x squared add up to 9x^2 and 5-5=0 so it has to be D

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What is the completely factored form of this polynomial? 25x^2y^2-100
Law Incorporation [45]

Answer:

25x²y² - 100

= 25(x²y² - 4)

= 25(xy + 2)(xy - 2)

3 0
2 years ago
The correlation coefficient for blood pressure and amount of vegetables eaten in a group of people is −0.7. Analyze the followin
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3 years ago
What is the combined weight of all the kittens? Weight of kittens: 1/4 pound: 3 kittens. 3/8 pound: 2 kittens. 1/2 pound: 4 kitt
Naya [18.7K]

Answer:

6 pounds

Step-by-step explanation:

1/4 times 3 = 3/4

3/8 times 2: 6/8 = 3/4

1/2 times 4: 4/2 = 2

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5 0
3 years ago
Help me with this problem!
kipiarov [429]

Answer:

y = -(2/3)x + 3  

C

Step-by-step explanation:

The slope of the equation that was given is - 2/3

The slope in a slope intercept equation is the number in front of the x when the value of the number in front of the y = 1 and x and y are on opposite sides of the equal sign. Let's translate that.

The original equation is y = -(2/3)x + 5/3

  • y and x have to be on opposite sides of the equal sign [They are]
  • The slope is the number in front of the x. That's (-2/3).  That makes A incorrect.

Now you need to use the given point

The point is (-3 , 5) Put this into the equation that you have so far

y = (-2/3)x + b

y = 5

x = -3

5 = (-2/3)(-3/1) + b Substitute in the givens

5 = (-2 * -3)/3 + b Multiply -2 * - 3 = 6

5 = 6/3  + b          Divide the 6 by 3

5 = 2 + b               Divide

5 - 2 = b                Subtract 2 from both sides

3 = b                      Switch sides

b = 3

Answer y = (-2/3)x + 3 or C


8 0
2 years ago
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\bf 12,\underline{351}\impliedby \textit{3 hundreds, and 51 units, let's round that}&#10;\\\\\\&#10;\begin{array}{llll}&#10;300----- 50-----400\\&#10;\qquad \qquad \uparrow\qquad \qquad \qquad \uparrow  \\&#10;&#10;\begin{array}{llll}&#10;anything\ here\\&#10;rounds\ up\ to\\&#10;300&#10;\end{array}\quad&#10;\begin{array}{llll}&#10;anything\ here\\&#10;rounds\ up\ to\\&#10;400&#10;\end{array}&#10;\end{array}&#10;\\\\\\&#10;\textit{therefore, the hundreds value of 300, the 51 tips it over to 400}&#10;\\\\\\&#10;12,\underline{400}
3 0
3 years ago
Read 2 more answers
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