Answer:
1/3
Step-by-step explanation:
The formula for computing the sum of an infinite geometric series is
where r is between -1 and 1 and 
is the common ratio, and 
is the first term of the series.
So let's plug in:
I multiplied bottom and top by 10.
I divided top and bottom by 3.
The sum is 1/3.
Given:
The given system of equations is:
To find:
The solution to this system of equations by graphing.
Solution:
We have,
The table of values for first equation is:
x y
0 1
1 -1
Plot the points (0,1) and (1,-1) on a coordinate plane and connect them a straight line.
The table of values for second equation is:
x y
0 -4
2 -3
Plot the points (0,-4) and (2,-3) on a coordinate plane and connect them a straight line.
The graphs of given equations are shown in the below figure.
From the below figure, it is clear that the lines intersect each other at point (2,-3). So, the solution of the given system of equations is (2,-3).
Therefore, the solution to this system of equations is:
x-coordinate: 2
y-coordinate: -3
Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Answer:
B. A teacher compares the pre-test and post-test scores of students
Step-by-step explanation:
the answer is true, because it is a good example to compare the tests between students, we know that a matching pair design is a random model and is used when the experiment allows grouping subjects in pairs based on a variable and each pair will receive randomly a different handling, the answer A is not true because in the example all students are uniformly averaged and the variable is not correlated with subgroups, option c is incorrect because the variable was not randomized and generates classification bias and the option d is incorrect because the teacher compares a small sample as her class with a score of a total sample, but does not intervene on her students when selecting the corresponding group
Answer:
Lisa’s
Step-by-step explanation:
Ratio- Tall:Short
Lisa’s Class- 24:12
Paul’s Class- 15:20
