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Alex Ar [27]
1 year ago
8

4 How many 3-cup servings are in 4 cups? A. 1/2 B. 2/ C. 4 D. 12

Mathematics
1 answer:
anygoal [31]1 year ago
7 0
This questions stated differently so I’m assuming it’s 4?
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GEOMETRY HELP! Celeste is constructing the perpendicular bisector of ST⎯⎯⎯⎯⎯ . Which set of instructions explains a correct way
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Answer:

The answer is C.

Step-by-step explanation:

Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.

So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.

After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.

So, the correct match is option C )  Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.

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A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 pe
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2 years ago
Read 2 more answers
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

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