Answer:
The cube root of given expression is
.
Step-by-step explanation:
The given expression is
![\sqrt[3]{216x^9y^{18}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D)
It can be written as
Use the exponent property: 
![\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E3%28x%5E3%29%5E3%28y%5E6%29%5E%7B3%7D%7D)
![\sqrt[3]{216x^9y^{18}}=\sqrt[3]{(6x^3y^6)^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D%5Csqrt%5B3%5D%7B%286x%5E3y%5E6%29%5E%7B3%7D%7D)
![\sqrt[3]{216x^9y^{18}}=6x^3y^6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E9y%5E%7B18%7D%7D%3D6x%5E3y%5E6)
Therefore the cube root of given expression is
.
Answer:
Hey there!
15 is composite. A composite number has factors other than one and itself. 15 has factors 3 and 5.
Thus, 15 is composite.
Let me know if this helps :)
Answer:
Step-by-step explanation:
in a parallelogram diagonals bisect each other.
so mid points are same.
Let coordinates of D be (x,y)
mid point of AC=midpoint Of BD
(-2+5)/2=(x+3)/2
x+3=-3
x=-3-3=-6
x=-6
(3-3)/2=(2+y)/2
y+2=0
y=-2
so D is (-6,-2)
56=8*7=2^3*7=2*2*2*7
Hope that helped