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nexus9112 [7]
1 year ago
11

Which of the following is not a valid Java identifier? a. Factorial, b. anExtremelyLongldentifierlfYouAskMe, c. 2ndLevel, d. Iev

el2, e. highest$.
Computers and Technology
1 answer:
True [87]1 year ago
5 0

2ndLevel, option c is not a valid Java identifier.

<h3 /><h3> What are Java identifiers ?</h3>

In Java, an identifier is a group of one or more characters that is used to name variables, methods, classes, etc. There are requirements that must be followed in order to produce an identification. Additionally, because they have a fixed meaning in Java, some character sequences, such as keywords, reserved words, and literals, cannot be used as identifiers.

<h3>In Java, can keywords be used as identifiers?</h3>

Since these words are part of the grammar of the Java programming language, you cannot use them as variable names (or identifiers) for variables like int, for, class, etc. Here is a list of every single keyword used in Java programming. You are not permitted to use the IDs true, false, or null in addition to these terms. Due to the fact that they are literals.

To know more about Java Programming visit

brainly.com/question/12948162

#SPJ4

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2.24 Write the relevant Python expression or statement, involving a list of numbers lst and using list operators and methods for
miskamm [114]

Answer:

lst = [11, 603, 99, 7, 582, 1];

print("The index of the middle element: " + str(int(len(lst)/2)))

print("The middle element: " + str(lst[int(len(lst)/2)]))

lst.sort()

sorted_lst = lst.reverse()

print("The list in descending order: " + str(lst))

first_number = lst.pop(0)

lst.append(first_number)

print("New lst: "+ str(lst))

Explanation:

- Initialize a list

- Find the middle index, int(len(lst)/2)

- Find the middle element, lst[int(len(lst)/2)]

- Sort the list in descending order (First sort the list in ascending order than reverse it)

- Get the first element using <em>pop</em> method, and append it to the end using <em>append</em> method

- - - - -

a) 0 == 1 == 2 --> Always evaluates false

b) 2 + (3 == 4) + 5 == 7 --> Evaluates true

c) 1 < -1 == 3 > 4 --> Always evaluates false

3 0
4 years ago
The number of protons plus the number of nuetrons equal the <br> A.atomic weight<br> B.atomic number
mash [69]
Atomic mass will be the answer according to your question .
For ex - atomic mass of oxygen is equal to 8+8 I.e. 16
Hope u understand by this
5 0
3 years ago
Write a program to take in a time-of-day on the command-line as 3 integers representing hours, minutes, and seconds, along with
nexus9112 [7]

Answer:

In Python:

hh = int(input("Hour: ")) * 3600

mm = int(input("Minutes: ")) * 60

ss = int(input("Seconds: "))

seconds = int(input("Additional Seconds: "))

time = hh+ mm + ss + seconds

hh =  int(time/3600)

time = time - hh * 3600

mm = int(time/60)

ss = time - mm * 60

while(hh>24):

   hh = hh - 24

print(str(hh)+" : "+str(mm)+" : "+str(ss))

Explanation:

We start by getting the time of the day. This is done using the next three lines

<em>hh = int(input("Hour: ")) * 3600</em>

<em>mm = int(input("Minutes: ")) * 60</em>

<em>ss = int(input("Seconds: ")) </em>

Then, we get the additional seconds

<em>seconds = int(input("Additional Seconds: "))</em>

The new time is then calculated (in seconds)

<em>time = hh+ mm + ss + seconds</em>

This line extracts the hours from the calculated time (in seconds)

hh =  int(time/3600)

time = time - hh * 3600

This line extracts the minutes from the calculated time (in seconds)

mm = int(time/60)

This line gets the remaining seconds

ss = time - mm * 60

The following iteration ensures that the hour is less than 24

while(hh>24):

   hh = hh - 24

This prints the calculated time

print(str(hh)+" : "+str(mm)+" : "+str(ss))

6 0
3 years ago
16. The data selected to create a chart must include
Murljashka [212]

Answer:

B.column titles and row labels

8 0
3 years ago
Consider whether there are additional components that could be added to the IPv4 protocol to enhance its usefulness. What are th
geniusboy [140]

Answer:

There are no additional components that can be added to the IPv4 protocol to improve its utility

Explanation:

The IPv4 protocol was developed in 1983 and is still the most widely used version worldwide. It consists of a 32-bit binary number that is normally represented in decimal notation, with four digits separated by dots that take values between 0 and 255.

This system limits the IPv4 protocol to 4,000 million different addresses, a figure that in the eighties seemed sufficient but that in practice has been scarce due to the revolution of mobile devices and the impending development of the Internet of Things ( IoT) that will trigger the number of devices connected to the network.

So, there are no additional components that can be added to the IPv4 protocol to improve its utility, since the world is running out of IPv4 addresses and is being replaced by IPv6.

Hope this helps!

5 0
3 years ago
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