Answer:
3/4
Step-by-step explanation:
First of all, we need to calculate the slope of the line shown. This can be computed as:

where
is the increment along the y-direction
is the increment along the x-direction
We can choose the following two points to calculate the slope of the line shown:
(-3,2) and (0,-2)
And so, the slope of the line shown is

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

Using
, we find that a line perpendicular to the line shown should have a slope of

Hi, you've asked an unclear question. However, I inferred you may want to know the actual number of students represented by the percentages of 27%, and 61%.
<u>Explanation:</u>
Finding percentage usually involves performing two operations; multiplication and division.
First, all (100%) of respondents said they watched TV at least at some point during the day.
Next, 27% of respondents stated that they only watched television during prime time hours, in which the actual number of students represented by the percentage is calculated by dividing 27 by 100 and multiplying by 1000 =
.
Finally, we are told 61% of respondents stated that they spend prime time hours in their dorm rooms. The actual number of students represented by the percentage is calculated by dividing 61 by 100 and multiplying by 1000 =

Answer:
314.16
Step-by-step explanation:
Area=πr2
d=2r
Solving for Area
A=1
4πd2=1
4·π·202≈314.15927
Answer:

The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is

we have



substitute

Find the domain for x
we know that

so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is
